bantuin saya matematika
[tex]a. 27^{\frac{2}{3}} = (3^3)^{\frac{2}{3}} = 3^{(3x\frac{2}{3})} =3^2=9\\\\b. 625^{-\frac{1}{4}} = (5^4)^{-\frac{1}{4}} =5^{(4x-\frac{1}{4})} =5^{-1}=\frac{1}{5}\\\\c. 25^{\frac{2}{3}} = (5^2)^{\frac{2}{3}} = 5^{(2x\frac{2}{3})} =5^{\frac{4}{3}}=(5^4)^{\frac{1}{3} }=\sqrt[3]{625} = \sqrt[3]{125x5}=5\sqrt[3]{5}\\\\[/tex]
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